-8x⁵-12x⁴+30x³+19x²-4x-10
Step-by-step explanation:
-8x⁵+10x³+4x²-12x⁴+15x²+6x+20x³-10x-10..simplify
-8x⁵-12x⁴+10x³+20x³+4x²+15x²+6x-10x-10... like terms
-8x⁵-12x⁴+30x³+19x²-4x-10.. this is the final answer we can't add this anymore cause they ain't like terms the last form is this one.
Menjawab:
1.1 cm
Penjelasan langkah demi langkah:
Volume kubus, V = a³
Dimana a = panjang sisi kubus
Untuk V = 1.331 cm³
Panjang sisi 'a' adalah:
V = a³
1,331 = a³
Ambil akar pangkat tiga dari kedua sisi
(1,331) ⅓ = a
a = 1,1 cm
Answer:
<h2>76</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>given:</h3>
<h3>tips and formulas:</h3>
- this is an isosceles triangle since two sides are equal therefore
- a triangle contains 180°
<h3>let's solve:</h3>
according to the question
2x+2+2x+2+3x+1=180
solve:
- collect like terms:7x+5=180
- substract 5 from both sides:=>7x+5-5=180-5=>7x=175
- divide both sides by 7: =>7x/7=175/7
given:
M∠R=3x+1
substitute the value of x
3×25+1
75+1
76
Answer:
Given : The high school stadium contains a track that surrounds a soccer field. The soccer field is 100 yards long and 70 yards wide.
The school decided to cover the semicircles with grass to create a space for stretching and other activities.
To Find: area of one of the semicircles at either end of the track
How many square yards of grass will the school need to cover the entire circle?
Solution:
Diameter of semicircle = 70 yards
Radius of semicircle = 70/2 = 35 yards
Area of semicircle at one end = (1/2)πr²
= (1/2)(22/7)35²
= 1,925 sq yards
area of one of the semicircles at either end of the track = 1,925 sq yards
square yards of grass will the school need to cover the entire circle
= 2 x 1,925
= 3850 sq yards
distance around one of the semicircles at either end of the soccer field = πr = (22/7) 35 = 110 yards
distance around the inner lane of the track = 100 + 100 + 110 + 110
= 420 yards
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