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Iteru [2.4K]
2 years ago
15

# How would you teach English Subject at your Bridge course class,if you were an English Teacher? ​

Mathematics
1 answer:
Len [333]2 years ago
7 0

english and maths teacher

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Define terminating.math​
tiny-mole [99]

Answer:numbers

Step-by-step explanation:

numbrres and letters

8 0
1 year ago
A spinner has 5 sector's of equal size. The sectors are labeled 1,2,3,4, and 5. the spinner is spun twice.x is the number of tim
LuckyWell [14K]

Answer:

Because the sectors are of equal size, each sector has the same probability of happening.

So for every number, you have a probability of 0.2 of it appearing.

Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.

So what is the probability to have 0 odd number in two spins?

What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.

What is the probability to have 2 odd numbers in two spins?

To verify if we did a good job, we add all the probabilities. We should get 1.

.

So to slide your bars, you slide them up to the number I gave you for each case.

Hope this helps!

8 0
3 years ago
Help please thank you sm
vitfil [10]
The correct answer is 5/21
5 0
3 years ago
Which of the following is the solution of 2x + 14 = 22?<br> x = 4<br> O x=8<br> X = 11<br> OX= 14
Tresset [83]

Answer:

x=4

Step-by-step explanation:

2x + 14 = 22

Subtract 14 from each side

2x+14-14 = 22-14

2x = 8

Divide by 2

2x/2 = 8/2

x = 4

7 0
3 years ago
A class comprises 26 students. During a mathematics test, one student made 12 mistakes but everyone else in the class made fewer
Rainbow [258]

Answer:

See explanation

Step-by-step explanation:

There are 26 students at the class.

During a mathematics test, one student made 12 mistakes but everyone else in the class made fewer mistakes than he did. So, all other students made 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 or 0 mistakes (12 different possibilites).

Suppose that at most 2 students in the class made the same number of mistakes. Hence, at most 12\cdot 2=24 students satisfy this condition. If we add that student who made 12 mistakes, the maximum total number of students in the class could be

24+1=25 students.

But the total number of students is 26, so our hypothesis is incorrect, thus there are at least 3 students in the class who made the same number of mistakes.​

3 0
4 years ago
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