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lapo4ka [179]
2 years ago
14

A bag has more green balls than blue balls, and there is at least one blue ball. Let b represent the number of blue balls and le

t g represent the number of green balls.Let's compare the expressions 2b and b + g. Which statement is correct?
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
5 0

Answer:

You must show us the statements that are given. This question can not be answered without that information. Have a nice day!!! :-)

Step-by-step explanation:

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!!WILL MARK BRAINLIEST!!!<br> plz help its due today!!
kirill115 [55]

Answer:

3 units right 1 unit up

Step-by-step explanation:

just observe one point that exactly the same on the new abcd and start from counting left/right then up/down

8 0
2 years ago
What is the coefficient of the second term in this expression?9–6w–5y
Ber [7]

Answer:

The coefficient of the second term in this expression is 6.

Step-by-step explanation:

A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression. There are three terms in this expression (9, 6w, and 5y), and the coefficient of the second term is 6.

4 0
2 years ago
Which set of numbers is included in the solution set of the compound inequality? {–7, 5, 18, 24, 32} {–9, 7, 15, 22, 26} {16, 17
Vesnalui [34]

Answer:

{-7,5,18,24,32}

Step-by-step explanation:

Let's verify all cases to determine the solution to the problem.

CASE A) we have

-9,7,15,22,26

The number 22 is not included in the solution set of the compound inequality.

CASE B) we have

-7,5,18,24,32

The number 22 is not included in the solution set of the compound inequality.

CASE C) we have

16,17,22,23,24

The number 22 is not included in the solution set of the compound inequality.

CASE D) we have

18,19,20,21,22

The numbers 19,20,21,22 are not included in the solution set of the compound inequality.

4 0
3 years ago
Read 2 more answers
A bag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn find each probability
iogann1982 [59]
#1) 5/20
#2) 7/300
#3) 3/50
#4) 5/20

Explanation
For #1:
There are 15 even numbers out of 30.  Since it is replaced before drawing the second ball, there will be 15 odd numbers out of 30.  This gives us
15/30(15/30) = 225/900 = 5/20.

For #2:
There is 1 7 out of 30; then there are 14 numbers greater than 16 out of 30:
1/30(14/30) = 14/900 = 7/300

For #3:
There are 6 multiples of 5 out of 30; then there are 9 prime numbers out of 30:
6/30(9/30) = 54/900 = 3/50

For #4:
There are 15 even numbers out of 30; then there are still 15 even numbers out of 30:
15/30(15/30) = 225/900 = 5/20
7 0
3 years ago
Read 2 more answers
Mr. Smith's first test's data: 55, 42, 78, 99, 69, 83, 74, 83, 97. The third step in creating a Box-and-Whisker plot is to deter
Serga [27]
The value of Q3 is 4 i think.
7 0
3 years ago
Read 2 more answers
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