Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
I think it might be the 3 one and if that's not right then it would be the first one.
Answer:
The answer is
<h2>70</h2>
Step-by-step explanation:
3b² - b
when b = 5
Substitute the value of b that's 5 into the expression
That's
3(5)² - 5
= 3(25) - 5
= 75 - 5
We have the final answer as
<h3>70</h3>
Hope this helps you
You would cross multiply for this.
20 ·
35 = 700
Then you would divide.
700 ÷
50 = 14
There would be
14 cones placed along 35 feet of road.
