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Fed [463]
2 years ago
14

Question 12

Mathematics
1 answer:
ANEK [815]2 years ago
7 0

The required x = $2,831.49. Option B) is correct.

7-year loan of $20,000 to Breck Inc. To repay you, Breck will pay $2,500 at the end of Year 1, $5,000 at the end of Year 2, and $7,500 at the end of Year 3, plus a fixed but currently unspecified cash flow, X, at the end of each year from Year 4 through Year 7.

<h3>What is invesment?</h3>

When some apply there money on something so that he can get higher value in returns of his money.

for the final 4 years

20000=2500/1.08+5000/(1.08^2)+7500/(1.08^3)+x/(1.08^4)+x/(1.08^5)+x/(1.08^6)+x/(1.08^7)

x = $2,831.49

Thus the required value of x = $2,831.49.


Learn more about investment here:
brainly.com/question/15105766

#SPJ1

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A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n
Ratling [72]

Answer:

a)

k = \dfrac{1}{21}

b) 0.476

c) 0.667    

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

P(y) = ky

a) Property of discrete probability distribution:

\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}

b) at most four forms are required

P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476

c) probability that between two and five forms (inclusive) are required

P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667

8 0
3 years ago
Find the inverse of the function
lozanna [386]

as you already know, to get the inverse of any expression we start off by doing a quick switcheroo on the variables and then solving for "y", let's do so.

\stackrel{h(x)}{y}~~ = ~~6\sqrt[3]{2x+5}-1\implies \stackrel{\textit{quick switcheroo}}{x~~ = ~~6\sqrt[3]{2y+5}-1} \\\\\\ x+1=6\sqrt[3]{2y+5}\implies \cfrac{x+1}{6}=\sqrt[3]{2y+5}\implies \left( \cfrac{x+1}{6} \right)^3=\left( \sqrt[3]{2y+5} \right)^3

\left( \cfrac{x+1}{6} \right)^3=2y+5\implies \left( \cfrac{x+1}{6} \right)^3-5=2y\implies \cfrac{\left( \frac{x+1}{6} \right)^3-5}{2}=y \\\\\\ \cfrac{\left( \frac{x+1}{6} \right)^3}{2}-\cfrac{5}{2}=y\implies \cfrac{~~ \frac{(x+1)^3}{6^3}~~}{2}-\cfrac{5}{2}=y\implies \cfrac{(x+1)^3}{432}-\cfrac{5}{2}=\stackrel{y}{h^{-1}(x)}

4 0
2 years ago
Please help ! ASAP step by step explanation please ​
fredd [130]

Answer:

0

Step-by-step explanation:

→ First find inverse cosine 1/2

60°

→ Now multiply this answer by 3 because then if you substitute it in you get 0.5

∝ = 180°

→ Now find sine of 180°

0

3 0
2 years ago
I need help ASAP please
anyanavicka [17]

Answer:

In the picture above.

Step-by-step explanation:

I hope that it's a clear solution.

Good luck:)

7 0
3 years ago
Can some one please answer this question I'm stuck.
Ainat [17]

Answer:

7

Step-by-step explanation:

Mean = 6

so work backwards.

6 x 4 = 24

24 = total amount of all cards added together.

24 - 4 - 6 - 7 = 7

8 0
3 years ago
Read 2 more answers
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