3 years ago

Read the instructions and then answer the questions

Mathematics

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

2) $x - y = \frac{2}{3}$

$= > x = \frac{2}{3} + y = \frac{2 + 3y}{3}$

3) $3x + 2y = 6$

$= > 3x = 6 - 2y$

$= > x = \frac{6 - 2y}{3}$

4) $\frac{1}{4} x + y = 2$

$= > y = 2 - \frac{x}{4} = \frac{8 - x}{4}$

5) $4x - 3y = - 33$

$= > 3y = 4x + 33$

$= > y = \frac{4x + 33}{3}$

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10. Given that the total distance travelled is 4 km and that the initial aceleration is 4 m/s², find:a) the value of V.b) the va

andrezito [222]

The initial deceleration is 4 m/s^2, so this means that considering the first line segment, $\frac{V-100}{T}=-4 \implies V=100-4T$ .

The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so $400T-\frac{1}{2}(100-V)(5T)=4000$ .

$400(100-4T)-\frac{1}{2}(4T)(5T)=4000\\\\40000-1600T-10T^2=4000\\\\10T^2 +1600T-36000=0\\\\T^2 +160T-3600=0\\\\(T+180)(T-20)=0\\\\T=20 (T > 0)\\\\\therefore V=100-4(20)=20$