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3 years ago

11

Read the instructions and then answer the questions

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

2) $x - y = \frac{2}{3}$

$= > x = \frac{2}{3} + y = \frac{2 + 3y}{3}$

3) $3x + 2y = 6$

$= > 3x = 6 - 2y$

$= > x = \frac{6 - 2y}{3}$

4) $\frac{1}{4} x + y = 2$

$= > y = 2 - \frac{x}{4} = \frac{8 - x}{4}$

5) $4x - 3y = - 33$

$= > 3y = 4x + 33$

$= > y = \frac{4x + 33}{3}$

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The amount of time it takes an ice cube to melt varies inversely to the air temperature. At 30 degrees Celsius, the ice will mel

Anon25 [30]

Answer:

hope this helps A block of ice melts in 2.5 hours when the temperature is 54 degrees.

Step-by-step explanation:therefore you can increase 2.5 and decrease 54 to whatever number you need

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3 years ago

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White raven [17]

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Step-by-step explanation:

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2 years ago

What value of a makes the equation true?<br> a+29=-63<br><br> I need help!!

irakobra [83]

Answer:

a = -92

Step-by-step explanation:

<u>Step 1: Subtract 29 from both sides</u>

a + 29 = -63

a + 29 - 29 = -63 - 29

<em>a = -92</em>

<em />

Answer: a = -92

7 0

3 years ago

Read 2 more answers

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

5 0

3 years ago

6x^2-2x+1=0 solve for x

Paraphin [41]

Solve by using the quadratic formula.

x=1+-i√5 / 6

6 0

4 years ago