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2 years ago

FOR 50 POINTS!

Mathematics

1 answer:

Elina [12.6K]2 years ago

4 0

The value of x in the equation is 2.

<h3>What is indices?</h3>

Indices singular index is a branch of algebra that deals with the power or exponent of variables.

Laws of indices help us to evaluate indicial expressions and equations.

Analysis:

$4^{8-2x}$ = 256

Here 4 is the base number while 8-2x is the exponent or index.

So for us to evaluate this, we need to write 256 in its index form having its base as 4 also.

so 256 in base 4 index form is $4^{4}$

$4^{8-2x}$ = $4^{4}$

since both sides have the same base number, we equate only their exponent

8-2x = 4

-2x = 4 - 8

-2x = -4

x = -4/-2 = 2

Learn more about indices: brainly.com/question/10339517

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(7i)(7i)<br>help! please show steps

exis [7]

Answer:

-49

Step-by-step explanation:

multiply 7 with 7 then i with i and lastly multiply the result numbers

7i × 7i ➡ 7 × 7 = 49

i × i = i^2

49 × i^2 = 49i^2

i^2 = -1 ➡ 49 × (-1) = -49

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3 years ago

Help please picture attached

Naya [18.7K]

Answer:

-10

Step-by-step explanation:

3/5(b)=-6

Divide -6 by 3/5, you get -30/3.

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3 years ago

Katie,Elizabeth,and Siobhan volunteer at the hospital. In a week,Katie volunteers 3 hours more than Elizabeth does and Siobhan v

Tema [17]

Let's say that x represents hours that Elizabeth volunteers over 1 week. Katie volunteers x+3 and Siobhan x-1 hours per week. The equation that arises from condition in text is:
3*(x+3) = 3*(x + x-1)
x+3 = 2*x - 1
2*x - x= 3+1
x=4.

Elizabeth volunteers    7 hours
Katie volunteers    4 hours
Siobhan volunteers   3 hours

7 0

3 years ago

Read 2 more answers

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

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3 years ago

Please explain number 10 in a step by step process.

Aleonysh [2.5K]

Good evening ,

______________

Answer:

a=3

___________________

Step-by-step explanation:

Look at the photo below for the answer.

3 0

3 years ago

Read 2 more answers