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stellarik [79]
1 year ago
12

SOMEONE, PLEASE ANSWER THIS!

Mathematics
2 answers:
IrinaVladis [17]1 year ago
8 0

Answer:

Step-by-step explanation:

Solution

Start with the product

The product is 7*x where x is a number but not specified.

Now add 6

Answer: 7x + 6      

This cannot be simplified any more than what it is now.

Troyanec [42]1 year ago
7 0
<h3>Question -:</h3>

Represent the following sentences as an algebraic expression:

  • 6 is added to the product of 7 and a number.
<h3>Explanation -:</h3>

<em>Assuming</em><em>:</em>

  • Let us assume the number as x.

<u>6</u><u> </u><u>is added to the product of 7 and a number.</u><u> </u>

Product : 7 × x = 7x

Now we will add 6.

Add : 7x + 6.

<em>Final </em><em>Answer</em><em>:</em>

7x + 6.

\star\tiny\pmb{spbankingandsscseries}  \small\star

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a fair coin is flipped 10 times. what is the probability of getting the same number of heads and tails
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3 0
2 years ago
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
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