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kolezko [41]
2 years ago
11

Consider the equation. Which graph shows a line that is perpendicular to the line defined by the given equation? A. In a linear

graph line diagram, A line passes through (minus 4, minus 2) and (2, minus 0.5) which intersects the x-axis at 4 units and the y-axis at minus 1 unit. B. In a linear graph line diagram, A line passes through (2, 0.5) and (minus 4, 2) which intersects the x-axis at 4 units and the y-axis at minus 1 unit. C. In a linear graph line diagram, A line passes through (2, 4) and (0.5, minus 2) which intersects the x-axis at 1 unit and the y-axis at minus 4 units. D. In a linear graph line diagram, A line passes through (2, minus 4) and (0.5, 2) which intersects the x-axis at 1 unit and the y-axis at minus 4 units.
Mathematics
1 answer:
Nikolay [14]2 years ago
6 0

The graph second represents the line that is perpendicular to the line y = 4x - 2 option  (B) is correct.

<h3>What is the slope?</h3>

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

\rm m =\dfrac{y_2-y_1}{x_2-x_1}

The question is incomplete:

The complete question is:

Consider the equation y = 4x - 2 Which graph shows a line that is perpendicular to the line defined by the given equation?

Please refer to the attached picture.

The given line:

y = 4x - 2

The slope of the line m = 4

The slope of the line which is perpendicular to the above line:

M = -1/4 = -0.25

The graph second has a slope of -0.25

\rm y\ -2\ =\ \dfrac{\left(2-0.5\right)}{-4-2}\left(x+4\right)

y - 2 = -0.25x - 1

y = -0.25x + 1

Thus, the graph second represents the line that is perpendicular to the line y = 4x - 2 option  (B) is correct.

Learn more about the slope here:

brainly.com/question/3605446

#SPJ1

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In which direction does the graph of the function shown below open?
sp2606 [1]

Answer:

D. Up

Step-by-step explanation:

When a parabola has the form  y=ax^2+bx+c , It is vertical (opens up or down).

Because the variable "x" is squared.

If  "a" is positive, then the parabola opens up, but if it is negative, then the parabola opens down.

In this case you have the quadratic function:

f(x) = 2x^2+5x-4

Which can be rewritten as:

 y = 2x^2+5x-4

Therefore, it is vertical, because it has the form:  y=ax^2+bx+c

You can observe that the value of "a" is:

a=2

Then, since "a" is positive, the parabola opens up.

5 0
3 years ago
Solve for a. a+(−4)=−13
dangina [55]
In your equation:  a+(-4)=-13
you then add four to each side, 
so a= negative 13 plus 4
so a=  -9
6 0
3 years ago
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chubhunter [2.5K]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
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Scientific notation
tatiyna

Answer:

51,760

Step-by-step explanation:

Move the decimal place 4 tens places to the right (Positively)

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I hope this helped!

7 0
2 years ago
During the first part of a​ trip, a canoeist travels 18 miles at a certain speed. the canoeist travels 4 miles on the second par
storchak [24]
We can set it up like this, where <em>s </em>is the speed of the canoeist:

\frac{18}{s} + \frac{4}{s-5} = 3

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):

s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s

If we rearrange this, we can turn it into a quadratic equation and factor:

18s - 90+4s=3 s^{2} -15s \\ 22s-90=3 s^{2} -15s \\ 3 s^{2} -37s+90=0 \\ (3s-10)(s-9)=0 \\ s= \frac{10}{3} ,9

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater."  We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

9-5 = 4

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
5 0
3 years ago
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