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VARVARA [1.3K]
3 years ago
5

Eight less than four times a number is less then 56. What are the possible values of that number?

Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

x < 16

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

Firstly, we should convert the question into a numerical function in order to visualize it better. Therefore, the function would look like so,

4x-8 < 56

Even though this is an inequality expression we can solve it like any Algebraic Expression. That being the case lets solve for x by getting x alone on one side.

4x-8 < 56 .... add 8 on both sides

4x < 64 ... divide both sides by 4

x < 16

Finally, we can see that the answer is x < 16

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Mashutka [201]3 years ago
5 0

Answer: B. X<12

Step-by-step explanation:

First we need to find out what number multipled by 4 is less than 56

4 x 12 = 48

56-48 = 8

And 4 is lower/less than 12 so that's why it's B

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6x+9y-12=0 ‎‎‎‎‎ ‎‎‎‎
77julia77 [94]

Answer:

x = 2

Step-by-step explanation:

6x + 9y - 12 = 0 \\ 6x + 9 \times 0  - 12 = 0 \\ 6x + 0 - 12 = 0 \\ 6x - 12 = 0 \\ 6x  = 12 \\ x = 2

6 0
2 years ago
Please show all work and not just the answers.
Nuetrik [128]

I hope this helps you

3 0
3 years ago
Solve for q. 3(q-7)=26 q=
TEA [102]

Answer:

3(q - 7) = 27

3q - 21 = 27

3q = 27 +21 = 48

q  = \frac{48}{3}  = 16

6 0
3 years ago
Read 2 more answers
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
What percent of 315 is 63?
telo118 [61]

Answer:

20%

Step-by-step explanation:

Write the problem as a mathematical expression.

63/315

Convert to decimal

0.2

Times by 100

0.2 times 100

20%

3 0
3 years ago
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