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Sindrei [870]
2 years ago
5

Evaluate each expression express the result in scientific notation PLSSS I NEED THIS QUICK AND INCLUDE THE EXPLANATION

Mathematics
1 answer:
Anna71 [15]2 years ago
6 0

Answer:

3.1 × 10^5

Step-by-step explanation:

8.37 ÷ 2.7= 3.1 when you divide you subtract the exponents

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Solve and simplify<br> 3. (y^2-7y-5)-(-3y^2+3y-4)
yKpoI14uk [10]

(y^2-7y-5)-(-3y^2+3y-4)=y^2-7y-5-(-3y^2)-3y-(-4)\\\\=y^2-7y-5+3y^2-3y+4

<em>combine like terms</em>

=(y^2+3y^2)+(-7y-3y)+(-5+4)=\boxed{4y^2-10y-1}

7 0
3 years ago
What is the median of the following data set?
Len [333]

Answer:

6

Step-by-step explanation:

First order them from least to greatest:

1, 3, 6, 7, 9

The median is 6 because it is the middle value.

Hope this helps! Brainliest would be really appreciated

5 0
2 years ago
Simplify square root of 2 over cube root of 2.
Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

\sqrt[n]{x}  =  {x}^{ \frac{1}{n} }

So you can rewrite the given fraction as

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }  =  {2}^{ \frac{1}{2} -  \frac{1}{3}  }

Since

\frac{1}{2}  -  \frac{1}{3}  =  \frac{3}{6}  -  \frac{2}{6}  =  \frac{1}{6}

the answer is

{2}^{ \frac{1}{6} }  \: or \:  \sqrt[6]{2}

3 0
3 years ago
Read 2 more answers
which set of numbers may represent the lengths of the sides of a triangle? A. 1, 3, 4 C. 5, 7, 9 B. 4, 4, 9 D. 8, 5, 3
enot [183]
The answer will be B 4,4,9
4 0
3 years ago
6.
Ilia_Sergeevich [38]

Answer:

  • A. 5 to the power of negative 5 over 6

Step-by-step explanation:

  • \sqrt[3]{5} \sqrt{5} /\sqrt[3]{5^5} =
  • 5^{1/3+1/2-5/3}=
  • 5^{1/2-4/3}=
  • 5^{3/6-8/6}=
  • 5^{-5/6}
6 0
2 years ago
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