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HACTEHA [7]
2 years ago
11

Help me solve the question

Mathematics
1 answer:
Svetach [21]2 years ago
8 0

Answer:

50.264 grams -> 50.2

Step-by-step explanation:

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Simplify: square root 27x12 over 300x8
alex41 [277]

Answer:

10

-------------

3x^2

Step-by-step explanation:

First lets simplify what is inside the square root

300x8

---------------

27x12

3 * 100 x^8

------------------

3 *9 x^12

The 3's cancel  and we know a^b/ a^c = a^(b-c)

100/9 x^ (8-12)

100/9 x^-4

sqrt( 100/9 x^-4)

Put the negative exponent in the denominator and make it positive

sqrt( 100 / (9x^4) )

We know that sqrt( a / b) = sqrt(a) / sqrt( b)

sqrt(100)

----------------

sqrt( 9x^4)

10

-------------

3x^2

Read more on Brainly.com - brainly.com/question/12900964#readmore

5 0
3 years ago
How do i solve this?
storchak [24]
I hope it help you bye

6 0
3 years ago
Read 2 more answers
-8y2 - 10y = 0 solve polynomial
iragen [17]

Answer:  y = 0, 5/4

hope this helps

4 0
3 years ago
A=b=c=0.8 Area (trigonometry)
attashe74 [19]

Answer:

Step-by-step explanation:

5 0
3 years ago
The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

  • The range of the function is all real numbers less than or equal to 9.
<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

  • The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c  with the vertex \mathbf{(x_v,y_v)}

  • If a < 0, then the range is f(x) ≤ \mathbf{y_v}
  • If a > 0, then the range f(x) ≥  \mathbf{y_v}
  • Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

\mathbf{x_v = -\dfrac{b}{2a}}

Thus,

  • vertex \mathbf{(x_v,y_v)} = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

#SPJ1

5 0
2 years ago
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