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3 years ago

HELP ASAP PLEASE!!!!!!

Mathematics

2 answers:

irakobra [83]3 years ago

6 0

Answer:

plato users the answer is B (x+5.5)^2+(y+4)^2=12.25

Step-by-step explanation:

devlian [24]3 years ago

5 0

A = (2+9)/2

a = 11/2

a = 5.5

__________________

b = (4+4)/2

b = 4

__________________

d = √(9-2)²+(4-4)²

d = √7²+0²

r = 3,5

____________________

(x-a)² + (y-b)² = r²

(x-5.5)² + (y-4)² = 3,5²

(x-5.5)² + (y-4)² = 12.25

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2 years ago

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3 years ago

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was <u>$95,300</u>.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

<em>The amount of house after eleven years to the nearest hundred dollars is $95,300.</em>

Therefore, when Aria sold her house after eleven years it worth was $95,300.

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3 years ago