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1 year ago

An equation that defines y as a function of x is given. a. solve for y in terms of x and

Mathematics

1 answer:

Ymorist [56]1 year ago

4 0

Answer:

f(x) = 2x -2/3
f(3) = 5 1/3

Step-by-step explanation:

We solve an equation for a specific variable by using inverse operations to undo what is done to the variable. The resulting function is evaluated by substituting the given value for the variable.

We are given the equation ...

6x -3y = 2

Solving for y, we get ...

6x -2 = 3y . . . . . add 3y-2 to both sides

2x -2/3 = y . . . . . divide by 3

f(x) = 2x -2/3 . . . . write using functional notation

To find f(3), we use x=3 in the function.

f(3) = 2(3) -2/3 = 6 -2/3

f(3) = 5 1/3

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Leokris [45]

Answer:

the answer is 112

Step-by-step explanation:

901-789=112

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3 years ago

Find the positive difference between the two solutions to the equation <img src="https://tex.z-dn.net/?f=%20%5Cdisplaystyle%5Csq

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3 years ago

If you had half a dollar, three quarters, eight dimes, six nickels, and nine pennies, how much money would you have altogether?

hjlf

Answer:

$1.69

Step-by-step explanation:

Half a dollar = $0.50

Eight dimes = $0.80

Six nickels = $0.30

Nine pennies = $0.09

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2 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

What is the sum of the probability of drawing a green marble and the probability of not drawing a green marble?

andrey2020 [161]

Yo sup??

the answer is 1 because

P(E)+P(E')=1

where E is the event and

E' is the complement of the event

Hope this helps

3 0

3 years ago