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2 years ago

An equation that defines y as a function of x is given. a. solve for y in terms of x and

Mathematics

1 answer:

Ymorist [56]2 years ago

4 0

Answer:

f(x) = 2x -2/3
f(3) = 5 1/3

Step-by-step explanation:

We solve an equation for a specific variable by using inverse operations to undo what is done to the variable. The resulting function is evaluated by substituting the given value for the variable.

We are given the equation ...

6x -3y = 2

Solving for y, we get ...

6x -2 = 3y . . . . . add 3y-2 to both sides

2x -2/3 = y . . . . . divide by 3

f(x) = 2x -2/3 . . . . write using functional notation

To find f(3), we use x=3 in the function.

f(3) = 2(3) -2/3 = 6 -2/3

f(3) = 5 1/3

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Tom earned $72 walking dogs for 6 hours. How many total hours will it take tom to earn $96 in all? Solve using unit rates

slava [35]

Answer:

8 hours

Step-by-step explanation:

Step one:

Given data

Tom earned $72 walking dogs for 6 hours

amount earned = $72

time taken = 6 hours

Required

The time taken to earn $96

Step two:

let us find the unit rate of his earning

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3 years ago

En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

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3 years ago