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Oksi-84 [34.3K]
3 years ago
6

You have an ant farm with 35 ants. The population of ants in your farm will double every 3 months. The table shows the populatio

n growth of the ants over nine months. Decide whether the table represents a linear function or a nonlinear function. After one​ year, how many ants will there be in the ant​ farm?
Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

560 ants and non linear function

Step-by-step explanation:

12 months divided by 3 months is 4. 35 times 2 is 70. Again is 140. Again is 280. Again a 4th time is 560 ants. It is not linear because it does not increase the same amount each time.

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Write your solution as an inequality: If 3
inysia [295]

Answer:

3

Step-by-step explanation:

if the inequality is 3, it will be 3

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The United States Postal Service charges a
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Of the employees who work at Stalling Printing, 90% attended the safety procedures meeting. If 63 employees attended the meeting
LUCKY_DIMON [66]
There are 70 employees who work at Stalling Printing.

Take note that the 63 employees who attended the meeting represents 90% of the total number of employees working at Stalling Printing. To get the total number of employees or the 100% number of employees, divide 63 by its percentage, 90%.

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3 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

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3 years ago
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