Answer:
If a person is randomly selected from this group, the probability that they have both high blood pressure and high cholesterol is P=0.25.
Step-by-step explanation:
We can calculate the number of people from the sample that has both high blood pressure (HBP) and high cholesterol (HC) using this identity:
We can calculate the probability that a random person has both high blood pressure and high cholesterol as:
Answer:
a. 0.6588
b. 0.3978
c. 0. 279
Step-by-step explanation:
In the given question the success and failure are given the number of outcomes is fixed so binomial distribution can be applied.
Here success= p = 12 % or 12/100 = 0.12
failure = q= 1-p = 1-0.12 = 0.88
n= 10
Using binomial probability distribution
a. Probability that the number of selected adults saying they were too young is 0 or 1 is calculated as:
P (x=0,1) = 0.12 ⁰(0.88)¹⁰10 C0 + 0.12 (0.88)⁹ 10 C1= 1* 0.279 * 1 + 0.12 ( 0.3165) 10 = 0. 279 + 0.3978= 0.6588
b. Probability that exactly one of the selected adults says that he or she was too young to get tattoos is calculated as
P (x=1) = 0.12 (0.88)⁹ 10 C1= 0.12 ( 0.3165) 10 = 0.3978
c. Probability that none of the selected adults say that they were too young to get tattoos is
P (x=0) = 0.12 ⁰(0.88)¹⁰10 C0 = 1* 0.279 * 1 = 0. 279
Total number of volunteer students for a committee = 7
Number of committee = 5
Number of ways of selecting the committee from the 7 volunteers = 7C5 = 7!/(5!*2!) = 21 ways.
There are 21 ways in which the 5-committee member can be selected from the 7 volunteers.
If the number is 5 or greater you round it up
if its four or less you round down
To find the inverse function, interchange the variables and solve for y.
h^-1 (x) = -9 - 3x/2
