Monthly depreciation is calculated as follows:
65,000 (Cost) – 5,000 (Salvage Value) ÷ 60 (5 years X 12 months per year) = 1,000 in depreciation per month.
a) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 36,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 2,000
b) Accumulated depreciation from 1/1/12 to 5/1/15 is 40,000 (12 months for 2012, 2013, 2014, & 4 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
5/1/15
Cash (DR) 31,000
Accumulated Depreciation (DR) 40,000
Equipment (CR) 65,000
Gain on Sale of Equipment (CR) 6,000
c) Accumulated depreciation from 1/1/12 to 1/1/15 is 36,000 (12 months for 2012, 2013, & 2014).
Assuming that sale was a Cash sale, the journal entry would look like this:
1/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 36,000
Loss on Sale of Equipment (DR) 18,000
Equipment (CR) 65,000
d) Accumulated depreciation from 1/1/12 to 10/1/15 is 45,000 (12 months for 2012, 2013, 2014, & 9 months for 2015).
Assuming that sale was a Cash sale, the journal entry would look like this:
10/1/15
Cash (DR) 11,000
Accumulated Depreciation (DR) 45,000
Loss on Sale of Equipment (DR) 9,000
Equipment (CR) 65,000
Not my answers, but I hope this will help you. :)
Answer:
Done
Step-by-step explanation:
Answer: approximately 24
Step-by-step explanation:
We need to plot a regression line.
So we fit a model using the regression of Y on X, that an equation that predict Y for a given X using:
(Y -mean(Y ))= a(X-meanX)...........1
Where the formular of a is given the attachment.
N= the of individuals = 5
Y = amount of fat
X = time of exercise
mean(X )= sum of all X /N
= 131/5 = 26.2
mean(Y) = sum of all Y/N
= 104/5 = 20.8
a = N(SXY) - (SX)(SY)/ NS(X²) -(SX)²......2
SXY = Sum of Product X and Y
SX= sum of all X
SY = Sum of all Y
S(X²)= sum of all X²
(SX) = square of sum of X
a = -0.478
Hence we substitute into 1
Y-20.8 = -0.478 (X-26.2)
Y -20.8 = -0.478X - 12.524
Y = -0.478X + 33.324 or
Y = 33.324 - 0.478X (model)
When X = 20
Y = 33.324 - 0.478 × 20
Y = 33.324 - 9.56
Y = 23. 764
Y =24(approximately)
Carefully meaning of formula used in attachment to the solution they are the same.
