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notka56 [123]
1 year ago
9

Cheryl plans to bake cookies tomorrow and needs to purchase chocolate chips and pecans for no more than $25 total. Chocolate chi

ps are $2 per pound and pecans are $5 per pound. Which of the following graphs correctly represents the scenario?
Mathematics
1 answer:
boyakko [2]1 year ago
6 0

The inequality that correctly represents this scenario is given as follows:

2x + 5y \leq 25

The graph is given at the end of the question.

<h3>What is a system of inequalities?</h3>

A system of inequalities is when two or more variables are related, and inequalities are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of chocolate chips purchased.
  • Variable y: number of pecans sold.

Chocolate chips are $2 per pound and pecans are $5 per pound. She wants to spend at most $25, hence:

2x + 5y \leq 25

More can be learned about a system of inequalities at brainly.com/question/3656398

#SPJ1

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Simplify this expression. <br> 6x2(3x)<br><br> 18x2 <br><br> 18x3<br><br> 108x2<br><br> 108x3
vazorg [7]
A) 18x2 = 36



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8 0
3 years ago
Whats 2/3 times negative 6/10
Fed [463]
The answer is
-  \frac{2}{5}
5 0
2 years ago
Can any help me please
PSYCHO15rus [73]
A = 8i + 6j
b = 4i + 5j

ab = (8i + 6j)(4i + 5j)
ab = 8i(4i + 5j) + 6j(4i + 5j)
ab = 8i(4i) + 8i(5j) + 6j(4i) + 6j(5j)
ab = 32i² + 40ij + 24ij + 30j²
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4 0
2 years ago
The average of Aaron's three test scores must be at least
nlexa [21]

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96

Step-by-step explanation:

6 0
3 years ago
Car A has an initial value of 30,000 and depreciates at a rate of 20% per year. Car B has an initial value of 20,000 and depreci
Doss [256]

Answer:

The value of Car B will become greater than the value of car A during the fifth year.

Step-by-step explanation:

Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.

In the attached excel file, the following are used:

Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000

Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000

Annual Depreciation expense of Car B in Year 7 =  Beginning value of Car B in Year 7 = 2,000

Conclusion

Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.

Download xlsx
4 0
2 years ago
Read 2 more answers
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