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SOVA2 [1]
3 years ago
14

What number between 67 and 113 is a multiple of 4,10,20

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

80 and 100 both qualify.

Step-by-step explanation:

You might be interested in
Whats the lcd of 1/7,14/17,12/13,5/6
gizmo_the_mogwai [7]
LCD (1/7, 14/7, 12/13, 5/6)

LCM = (7, 7, 13, 6)

=  2 * 3 * 7 * 13

=  546



1/7  = 78/546

14/7  = 1092/546

12/13  = 504/546

5/6  = 455/546




Calculation:

1/7 + 14/7 

= 1 + 14/7

=  15/7


The common denominator you can calculate as the least common multiple of the both denominators:   LCM (7, 7) = 7


Add:

15/7 + 12/13 

= 15 . 13/7. 13  + 12 . 7/13 . 7

= 195/91 + 84/91

=  195 + 84/91 

=  279/91


The common denominator you can calculate as the least common multiple of the both denominators:  LCM (7, 13) = 91



Add:

279/91 + 5/6

= 279 . 6/91 . 6 + 5 . 91/6. 91

= 1674/546 + 455/546

= 1674 + 455/546 

= 2129/546



The common denominator you can calculate as the least common multiple of the both denominators:  LCM (91, 6) = 546



Hence, 546 is the LCM/LCD of (1/7, 14/17, 13/13, 5/6).






Hope that helps!!!!!!


3 0
3 years ago
Help please!!! Find x and Y
Sav [38]

Answer:

x = 40

y = 15

Step-by-step explanation:

Given is an equilateral triangle.

Measure of each angle of an equilateral triangle is 60°.

Therefore,

(x + 20)° = 60°

x + 20 = 60

x = 60 - 20

x = 40

4y = 60

y = 60/4

y = 15

8 0
3 years ago
What is the perimeter of a rectangle with a length of 23 mm and a width of 26mm
NISA [10]

Answer:98mm

Step-by-step explanation:

You add the length and width together and then multiply by 2

4 0
3 years ago
Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
   4{¹/₂[1] - ¹/₂[cos(2x)]} = 5 - 4cos(x)
         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
     4[¹/₂] - 4[¹/₂cos(2x)] = 5 - 4cos(x)
                2 - 2cos(2x) = 5 - 4cos(x)
              - 2                   - 2
                    -2cos(2x) = 3 - 4cos(x)
            -2[2cos²(x) - 1] = 3 - 4cos(x)
               -4cos²(x) + 2 = 3 - 4cos(x)
                               - 2  - 2
                     -4cos²(x) = 1 - 4cos(x)
-4cos²(x) + 4cos(x) - 1 = 0
 4cos²(x) - 4cos(x) + 1 = 0
               [2cos(x) - 1]² = 0
                  2cos(x) - 1 = 0
                              + 1 + 1
                       2cos(x) = 1
                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
                                 x = π/3, 5π/3

[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
5 0
3 years ago
Add the fractions and give me the answer?
Sedaia [141]

Answer:

21/20

Step-by-step explanation:

you find a common multiple for the 4 and 5, and multiply to get it. In this case, it would be 20. So, you multiply 1 and 4 by 5 so it would be 5/20. And multiply 4 and 5 by 4 to get 16/20. 5/20+16/20 is 21/20.

5 0
3 years ago
Read 2 more answers
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