Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people =
Standard deviation of 50 people 
Then , the probability its maximum safe load will be exceeded =
![P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855](https://tex.z-dn.net/?f=P%28X%3E10000%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B10000-9500%7D%7B282.84%7D%29%5C%5C%5C%5C%3DP%28z%3E1.7671-8%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.7678%29%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3DP%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.96145%5C%20%5C%20%5C%20%5B%5Ctext%7B%20By%20p-value%20of%20table%7D%5D%5C%5C%5C%5C%3D0.03855)
Thus , the probability its maximum safe load will be exceeded = 0.03855
Answer:
<em>She need </em><em>72 </em><em>index cards.</em>
Step-by-step explanation:
Ms. James has a 6 square foot bulletin board and a 12 square food bulletin board and she wants to cover both boards with index cards without gaps or overlaps.
Each index card has an area of
square foot.
Dividing the area of each board with the area of the index card will yield the the number of cards she needs to cover up completely.
Let us assume T₁ and T₂ are the number of cards she needs to cover 6 square feet food bulletin board and 12 square feet food bulletin board respectively. So

Therefore, in total she need 24+48=72 index cards.
Answer:
It should be (2,9).
Step-by-step explanation:
If you rotate it counter clockwise, the x value and y value switch numbers and they will both become postive.
Answer:
Mildred is correct because she distributed 5 correctly
Step-by-step explanation:
We cannot tell exactly which solution goes with which student, but we believe you are saying ...
Mildred’s Solution:
5 (Negative 2 and one-fourth) = 5 (negative 2 minus one-fourth)
= negative 10 minus StartFraction 5 over 4 EndFraction
= negative 11 and one-fourth
This solution describes the correct distribution of 5. Whoever it belongs to gave the correct solution.
Step-by-step explanation:
18h=252
9h=?(x)
9×252=18x
2268=18x
2268/18=x
x=126