Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
The value of x is 49 and the value of AB is 90
Step-by-step explanation:
You know that AB and DE are congruent. That information is given to you.
You set the equations equal to each other and then solve.
2x - 8 = x + 38
Subtract x
x - 8 = 38
Add 8.
x = 49
Plug back into 2x - 8 to find the value of AB
2 times 49 - 8
98 - 8
90
Answer:
<u>-1=5.3</u>
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<em>not sure if this is right; it should be though</em>
<em></em>
Step-by-step explanation:
2.1(0) - (1+2(0))= 5.3
-(1)=5.3
-1=5.3
Answer:
hi
Step-by-step explanation:
hi
