Transform each graph as specified below.
1 answer:
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Answer:
Vertical asymptote at x= 6
Oblique asymptote at y=x+10
Step-by-step explanation:
To find out vertical asymptote , we take the denominator and set it =0
x-6=0 , so x=6
Vertical asymptote at x= 6
The degree of numerator is 2 and the degree of denominator is 1.
Here, the degree of numerator is higher than the degree of denominator. So there will be a slant or oblique asymptote. we can find it by long division.
x + 10
-------------------------------
x-6 x^2 + 4x -3
x^2 - 6x
-------------------------------(subtract)
10x - 3
10x - 60
-----------------------------(subtract)
57
Oblique asymptote at y=x+10