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kherson [118]
3 years ago
5

Walt received a package that is 2 1/3 inches long, 6 ¾ inches high, and 8 ½ inches wide. What is the surface area of the package

?
plz help
Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer:

The surface area of the prism is 185.815 square inches.

Hope this helps!

Umnica [9.8K]3 years ago
3 0

The surface area of prism is 185.815 square inches

<em><u>Solution:</u></em>

Given that,

Length = 2\frac{1}{3}\ inches = \frac{3 \times 2 + 1}{3} = \frac{7}{3}\ inches = 2.33\ inches

Width = 8\frac{1}{2}\ inches = \frac{17}{2}\ inches = 8.5\ inches

Height = 6\frac{3}{4}\ inches = \frac{27}{4}\ inches = 6.75\ inches

<em><u>The surface area of package is given as:</u></em>

A=2(wl+hl+hw)

Where,

"l" is the length

"w" is the width

"h" is the height

<em><u>Substituting the values we get,</u></em>

A = 2((8.5 \times 2.33) + (6.75 \times 2.33) + (6.75 \times 8.5))\\\\Simplify\ the\ above\ equation\\\\A = 2(19.805+15.7275+57.375)\\\\A = 2 \times 92.9075\\\\A = 185.815

Thus the surface area of prism is 185.815 square inches

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aleksandrvk [35]

The equation between the number of days remaining and number of hours is given as y= -5x+50.

<h3>How to illustrate the equation?</h3>

Let y be the number of days remaining and x be the no.of hours.

From the graph the slope of the line is given by m.

m=(y2 - y1)/(x2 - x1)

m=(30 - 40)/(4 - 2)

m= -10/2 = -5.

The above slope is in between points 2 and 4. As the line has a constant rate of growth the slope is the same between any points of the line.

Therefore the equation between the no.of days remaining and no.of hours is given by

y=mx +c.

y=-5x+c

Now to find the value of c. This can be determined by substituting the x and y values at a particular instant. For x=0,y=50. Therefore by these values, we get,

50= -5(0)+c

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Therefore the relation between the number of days remaining and number of hours is given as y= -5x+50.

Learn more about equations on:

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Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
katrin2010 [14]
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cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
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sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
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sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
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Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


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