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vesna_86 [32]
2 years ago
13

The graph below shows point P and line A. If line B is drawn such that it passes through point P and is parallel to line A, what

is the equation of line B? Give your answer in the form y = mx + c, where m and care integers or fractions in their simplest forms. The graph below shows point P and line A. If line B is drawn such that it passes through point P and is parallel to line A , what is the equation of line B ? Give your answer in the form y = mx + c , where m and care integers or fractions in their simplest forms .​

Mathematics
1 answer:
n200080 [17]2 years ago
6 0

Answer:

Step-by-step explanation:

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Dora drove 80 km in 40 minutes then 120 km in 1 hour and then the final 200km took him 1 hour 20 minutes. what is his average sp
bonufazy [111]

9514 1404 393

Answer:

  133 1/3 km/hour

Step-by-step explanation:

Average speed is computed as ...

  average speed = (total distance)/(total time)

  = (80 km +120 km +200 km)/(2/3 + 1 + 1 1/3 hour) = 400 km/(3 hour)

  = 133 1/3 km/hour

8 0
2 years ago
Write down the decimal equivalent to;
Nesterboy [21]
A) 25% = 25/100 = 0.25

b) 18% = 18/100 = 0.18

c) 40% = 40/100 = 0.40

d) 2% = 2/100 = 0.02

e) 0.15% = 0.15/100 = 0.0015
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B
riadik2000 [5.3K]

Let

S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n

where we assume |r| < 1. Multiplying on both sides by r gives

r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}

and subtracting this from S_n gives

(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}

As n → ∞, the exponential term will converge to 0, and the partial sums S_n will converge to

\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}

Now, we're given

a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a

a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}

We must have |r| < 1 since both sums converge, so

\dfrac{15}a = \dfrac1{1-r}

\dfrac{150}{a^2} = \dfrac1{1-r^2}

Solving for r by substitution, we have

\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)

\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}

Recalling the difference of squares identity, we have

\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}

We've already confirmed r ≠ 1, so we can simplify this to

\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15

It follows that

\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12

and so the sum we want is

ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0
2 years ago
Marvin counts six $5 bills. write each value that he counts. what pattern do you see in the one digits of the values he counts?
spin [16.1K]
Answer: If the number of bills counted is odd, the ones digit is 5; if the number of bills is even, the ones digit is 0.

Explanation

1) Simulate the counting of the bills:

number of bills counted          value              ones digit

1                                             5                         5

2                                             5 + 5 = 10           0

3                                             10 + 5 = 15         5

4                                             15 + 5 = 20         0

5                                              20 + 5 = 25        5

6                                              25 + 5 = 30        0

2) Pattern: you can see that the ones digit alreternate: 5, 0, 5, 0, 5, 0, ...

If the number of bills counted is odd the ones digit is 5, if the number of bills is even the ones digit is 0.
4 0
3 years ago
What is the solution to the following system of equations?
Semmy [17]

Answer:

(3,2)

Step-by-step explanation:

The system is

x + y = 5

x -y = 1

Add the equations to eliminate y

2x = 6----->x=3

Substitute this value in any equation

3+y = 5----->y=2

The solution is (3,2)

3 0
3 years ago
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