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Paha777 [63]
2 years ago
7

A car travels 500 miles at an average speed of 60 MPH on the return trip the same route that it travels 50 miles per hour how lo

ng would it take?
​
Mathematics
1 answer:
xxMikexx [17]2 years ago
7 0

Step-by-step explanation:

it is not clear - is 500 miles the whole round trip, or is it only the trip in one direction ?

and do we need the time for the whole round trip, or only for the return trip ?

in any case, always remember,

speed = distance/time

therefore, to get time, we need to divide distance by speed :

distance / distance/time = time×distance/distance = time

so, let's calculate all these different scenarios :

1. 500 miles is only one direction, and we measure only the time going back with 60 mph :

500 / 60 = 50/6 = 25/3 = 8 1/3 = 8 hours 20 minutes.

as 1/3 of 1 hour = 1/3 of 60 minutes = 60/3 = 20 minutes.

2. 500 miles is only one direction (going 1000 miles altogether), and we measure the time going to with 50 mph and going back with 60 mph :

500 / 50 = 10 hours

500 / 60 = 8 hours 20 minutes

the whole round trip takes 18 hours 20 minutes.

3. 500 miles is the whole round trip. so, 250 miles is one direction. and we measure only the time going back with 60 mph :

250 / 60 = 25/6 = 4 1/6 = 4 hours 10 minutes.

as 1/6 of 1 hour = 1/6 of 60 minutes = 60/6 = 10 minutes.

4. 500 miles is the whole round trip. so, 250 miles is one direction. and we measure the time going to with 50 mph and back with 60 mph :

250 / 50 = 5 hours

250 / 60 = 4 hours 10 minutes

the whole round trip takes 9 hours 10 minutes.

did you notice ?

when going only half the distance, also the time it takes to travel that distance is only half (or vice versa - double). because the ratio distance/time is always the same.

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Step-by-step explanation:

Problem 1:

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Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

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