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snow_lady [41]
3 years ago
10

The function P(d) = 1 + + gives the pressure, in atmospheres (atm), at a depth d feet in

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer:

c) 39; At a depth of 59 feet, the pressure is atm.

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Mrs. Clearwater paid $38.64 to fill up 12 gallons of gasoline in her car. What is the price for 1 gallon of gasoline?
vfiekz [6]

Answer: $3.22

Step-by-step explanation:

We will start by doing 38.64 divided by 12

Then we will get the answer 3.22.

$3.22 is the answer.

6 0
2 years ago
Read 2 more answers
(3x+2) and (5x-6) solve for x
HACTEHA [7]

Answer:

x=3X 2 + 5x -6

Step-by-step explanation:

3X2 + 5X-6= 3X2 + 5X 6

X=3X2 +5X -6

6 0
3 years ago
Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
[PICTURE ATTACHED] HHEELLPPP<br><br> btw look at both of the pics
Natalija [7]
I think that it is the first line. I am not really sure what the question is asking so I may be wrong. Sorry if I can’t help
6 0
3 years ago
Solve the following equation 2/3x+6=1/2x+1/4x
Vanyuwa [196]

Answer:

x= 72

Step-by-step explanation:

combine the Xs on one side and then make the denominators the same and solve

8/12X +6 = 3/4X

sub 6 on both sides

then sub 3/4 (aka. 9/12)

-1/12X= -6

multiply by reciprocal (the fraction flip-flopped)(-12) on both sides

and you get 72

4 0
3 years ago
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