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Mathematics

1 answer:

gulaghasi [49]3 years ago

4 0

Answer:

Step-by-step explanation:

a) circumference = diameter*pi

so, pi in circle A =25.12/8=3.14

pi in circle B = 9.42/3 =3.14

b) area of the circle =(diameter/2)^2*pi

so pi in circle A = 50.24/(8/2)^2=3.14

pi in circle B = 3.14

C) both the value of circle A and B are equivalent

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Suppose there was a cancer diagnostic test was 95% accurate both on those that do and those do not have the disease. If 0.4% of

Musya8 [376]

Complete Question

Suppose there was a cancer diagnostic test was 95% accurate both on those that do and 90% on those do not have the disease. If 0.4% of the population have cancer, compute the probability that a particular individual has cancer, given that the test indicates he or she has cancer.

Answer:

The probability is $P(C | A) = 0.0042$

Step-by-step explanation:

From the question we are told that

The probability that the test was accurate given that the person has cancer is

$P(A | C) = 0.95$

The probability that the test was accurate given that the person do not have cancer is

$P(A | C') = 0.90$

The probability that a person has cancer is

$P(C) = 0.004$

Generally the probability that a person do not have cancer is

$P(C') = 1- P(C)$

=> $P(C') = 1- 0.004$

=> $P(C') = 0.996$

Generally the probability that a particular individual has cancer, given that the test indicates he or she has cancer is according to Bayes's theorem evaluated as

$P(C | A) = \frac{P(A | C) * P(C)}{P(A|C) * P(C) + P(A| C') * P(C')}$