Answer:
Step-by-step explanation:
We are given D (7, -3) and D'(2, 5).
the transformation
D'(x,y) → D(x-5, y+8).
Then
x=7 → x=7-5 = 2
y=-3 → y=-3+8 = 5
Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
Answer:
Step-by-step explanation:
you divide the two to the y, which is x=3/2y
then, you simplify the second equation to y, which is -3y= -4x+12
then, you substitute the x=3/2y into the second equation,
-3y = -6+12
-3y = 6
y = -2
Substitute the y into the first equation, x= 3/2y,
x = -3
Answer:
Option 2 is correct.
Step-by-step explanation:
Given the coordinates of lines segment (3, 10) and (7, 8). we have to find the mid-point of given line segment.
Mid-point formula states that if 
and 
are the coordinates of end points of line segment then the coordinates of mid-point are
∴ Coordinates of mid-point of line segment joining the points (3, 10) and (7, 8) are
Hence, option 2 is correct.
