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pantera1 [17]
2 years ago
10

Angela and Michelle shared some money in the ratio 4: 9 then Angela gave Daniel half her share.Michelle gave Daniel a third of h

er share. Daniel was given a total of £20. Work out how much money was originally shared.​
Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0

Using a system of equations, it is found that £52 was originally shared.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Angela's share.
  • Variable y: Michelle's share.
  • Variable z: Daniel's share.

Angela and Michelle shared some money in the ratio 4: 9, hence, considering t as the total:

  • x = \frac{4t}{13}.
  • y = \frac{9t}{13}

Angela gave Daniel half her share.Michelle gave Daniel a third of her share. Daniel was given a total of £20, hence:

\frac{x}{2} + \frac{y}{3} = 20

\frac{4t}{26} + \frac{9t}{39} = 20

\frac{12t + 18t}{78} = 20

30t = 20 x 78

t = 20 x 78/30

t = £52.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0
3 years ago
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