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wlad13 [49]
1 year ago
5

Adrian exercised three days during the past week. He exercised 58 minutes and 45 seconds during the

Mathematics
1 answer:
aniked [119]1 year ago
3 0

Answer:

2h 1' 1"

Step-by-step explanation:

1h = 1 hora

1' = 1 minute

1" = 1 secind

The sum of the three days is:

  58'  45"

+ 40'  40"

  20'  36"

= 118'  121"

118' 121" = 118' + 121"

1' = 60"

121" = 120" + 1"  = (120/60) + 1 = 2' + 1"

Then:

118' + 121" = 118' + 2' ´+ 1" = 120' + 1"

1 h = 60'

(120/60) + 1 = 2h + 1'

then:

118' + 121" = 2h + 1' + 1"

= 2h 1' 1"

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Step-by-step explanation:

<h3><em><u>Given</u></em><em><u>:</u></em></h3>

Length of the rectangle = 6.5 m

Width of the rectangule = 7.3 m

<h3><em><u>Then</u></em><em><u>:</u></em></h3>

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<u>Second</u><u> </u><u>case</u><u>,</u>

Perimeter of the rectangle

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2 years ago
Read 2 more answers
PLEASE HELP I NEED THIS ASAP<br> Find the vertex of y=x^2-7x+4
Goshia [24]

Answer:

\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

Step-by-step explanation:

y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\

\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)

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