Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
Step-by-step explanation:
you should only make one equation:
75 + 45x = 30 + 55x
subtract the 30 frim both sides, then subtract 45x from both sides. you are left with:
45 = 10x
Divide by 10 and get:
4.5 = x
After 4.5 hours, the cost is equal for either worker.
If he paid $57 monthly for 14 months, the total amount paid is:

He paid $798 in total
You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.

÷

⇒

×

Now you multiply across. 2×15=30 and 3×11=33
So now it is

-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor
The GCF is 3
Divide both the numerator and denominator by 3

÷

=

Answer: