Answer:
There is enough evidence to make the conclusion that the population mean amount of time to assemble the Meat Man barbecue is not equal to 10 minutes (P-value=0.009).
Step-by-step explanation:
We have to perform an hypothesis test on the mean.
The null and alternative hypothesis are:
The significance level is 
.
The test statistic t can be calculated as:
The degrees of freedom are:
The P-value (two-tailed test) for t=2.737 and df=49 is P=0.00862.
This P-value (0.009) is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.
There is enough evidence to make the conclusion that the population mean amount of time to assemble the Meat Man barbecue is not equal to 10 minutes.
Answer:
128 ft / second.
Step-by-step explanation:
It's acceleration is due to gravity and is 32 ft s^-2.
To find the velocity when it hits the ground we use the equation of motion
v^2 = u^2 + 2gs where u = initial velocity, g = acceleration , s = distance.
v^2 = 0^2 + 2 * 32 * 256
v^2 = 16384
v = 128 ft s^-1.
(2x^2 -5y)/(3x-y)
((2*2)^2-(5*-4))/((3*-4)-(-4))
(4^2+20)/(-12+4)
36/-8
-4.5
{(-5,64), (2,1)}
linear equation: y = -9x + 19
quadratic equation: y = x² - 6x + 9
Substitute the y in the quadratic equation by the its value in the linear equation.
-9x + 19 = x² - 6x + 9
- 19 - 19 *subtract 19 to both sides
-9x = x² - 6x -10
+9x + 9x *add 9x to both sides
0 = x² + 3x - 10
0 = (x + 5) (x - 2) *Factor
Set each factor = 0 and solve
x + 5 = 0 ; x - 2 = 0
x = -5 ; x = 2
Find the corresponding value of y using the linear equation.
y = -9x + 19
x = -5 x = 2
y = -9(-5) + 19 y = -9(2) + 19
y = 45 + 19 y = -18 + 19
y = 64 y = 1
(-5,64) (2,1)
Check each value on each equation.
y = x² - 6x + 9
(-5,64) (2,1)
64 = (-5)² - 6(-5) + 9 1 = 2² - 6(2) + 9
64 = 25 + 30 + 9 1 = 4 - 12 + 9
64 = 64 1 = 1
y = -9x + 19
64 = -9(-5) + 19 1 = -9(2) + 19
64 = 45 + 19 1 = -18 + 19
64 = 64 1 = 1
{(-5,64), (2,1)}
Answer:
(a) yes
(b) no; see below
Step-by-step explanation:
(a) Integer roots of the quartic will be integer divisors of 6. One of the divisors of 6 is 3, so 3 is a possible root.
(b) In order for 3 to be a double root, it would have to be a double factor of 6. The only integer factors of 6 are 1, 2, 3, 6. (3² = 9 is not one.)
___
The quartic can be written as ...
k(x -a)(x -b)(x -c)(x -d) . . . . . where a, b, c, d, k are integers
The constant term will be kabcd, of which each of the roots is a factor. If the constant is 6 and one root is d=3, then we must have
kabcd = 3kabc = 6
kabc = 6/3 = 2
Among these four integer factors, there must be an even number of minus signs, and one that has the value ±2. Another root whose value is 3 will not satisfy the requirements.
