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2 years ago

Determine which graph represents a reflection across the x-axis of f(x) = 3(1.5)x.

Mathematics

1 answer:

vivado [14]2 years ago

5 0

The reflection is written as:

$g(x) = -3*(1.5)^x$

And the graph can be seen below.

<h3>How to get the graph of the reflection?</h3>

Here we have the function:

$f(x) = 3*(1.5)^x$

A reflection across the x-axis is given by:

$g(x) = -f(x).$

Then, replacing the function f(x) by the actual equation:

$g(x) = -3*(1.5)^x$

The graph of the function g(x) can be seen below:

If you want to learn more about reflections:

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F(x)=x^2 reflected over x=2

klasskru [66]

Answer:

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Step-by-step explanation:

To reflect a graph, f(x) over the x-axis, you take -f(x). So if f(x)=x^2, then -f(x) is -x^2. Then g(x)=-x^2 is the reflection of your function f(x) over the x-axis.

3 0

2 years ago

Read 2 more answers

Initial value problems dy/dx+2y=3. Y(0)=1

Pavel [41]

The initial value equation is $y = \frac 12(3 - e^{-2x})$

<h3>How to solve the initial value?</h3>

The equation is given as:

$\frac{dy}{dx} +2y = 3$

Where

Y(0) = 1

Subtract 2y from both sides in the equation

$\frac{dy}{dx} = -2y + 3$

Rewrite as:

$\frac{dy}{-2y + 3} = dx$

Integrate both sides of the equation

$-\frac 12\ln|-2y + 3| = x + C_o$

Multiply through by -2

$\ln|-2y + 3| = -2x + C_1$

Take the exponent of both sides

$-2y + 3 = Ce^{-2x$

Next, we solve for C under the initial condition Y(0) = 1.

This gives

$-2(1) + 3 = Ce^{-2 * 0$

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in $-2y + 3 = Ce^{-2x$

$-2y + 3 = e^{-2x$

Next, we solve for y

$y = \frac 12(3 - e^{-2x})$

Hence, the initial value equation is $y = \frac 12(3 - e^{-2x})$

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2 years ago

For a continuous random variable x, the height of the function at x is a. 0.50, since it is the middle value. b. a value less th

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Answer:

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Step-by-step explanation:

A continuous random variable takes infinite number of possible values.

example include height , weight amount of sugar in an orange time required to run a mile.

Continues random variable named probability function f(x).

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3 years ago

Which set of line segments could create a right triangle? a 15, 30, 35 b 15, 36, 39 c 15, 20, 29 d 5, 15, 30

velikii [3]

<span>Which set of line segments could create a right triangle? a 15, 30, 35 b 15, 36, 39 c 15, 20, 29 d 5, 15, 30 = </span>b 15, 36, 39

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4 years ago

List the domain and range of the relation.<br> {(5,-5), (7,7), (0,-5), (7,1) (5,5)}

artcher [175]

Answer:

domain = (0,5,7)

range = (-5,1,5,7)

Step-by-step explanation:

domains are the x in (x,y) , and ranges are y in the (x,y) relations.

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3 years ago