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Korolek [52]
3 years ago
6

List the domain and range of the relation. ​{(5​,-5​), ​(7​,7​), ​(0​,-5​), ​(7​,1​) ​(5​,​5)}

Mathematics
1 answer:
artcher [175]3 years ago
4 0

Answer:

domain = (0,5,7)

range = (-5,1,5,7)

Step-by-step explanation:

domains are the x in (x,y) , and ranges are y in the (x,y) relations.

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G(x)=1/2(x-3)+1 find the inverse
Marysya12 [62]

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3 years ago
SOMEONE PLEASE HELP ME i really need this one
jek_recluse [69]

Answer:

Wait are u trying to find the area of a shape???

Step-by-step explanation:

8 0
3 years ago
Write an exponential function in the form y=ab^x that goes through points (0,9) and (3, 576)
sineoko [7]

Answer:

An exponential function in the form y=9(4ˣ)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that exponential function

                  y = a bˣ ...(i)

The equation (i) passes through the point (0,9)

               9 = a (b )⁰ = a

             a =9

<u><em>Step(ii):-</em></u>

The equation (i) passes through the point (3,576)

            576 = 9(b)³

         ⇒    \frac{576}{9} = b^{3}

      ⇒     64 = b³

     ⇒     4³ = b³

             (4^{3} )^{\frac{1}{3} } = (b^{3} )^{\frac{1}{3} }

             b = 4

<u><em>Final answer:-</em></u>

An exponential function in the form y=abˣ

An exponential function in the form y=9(4ˣ)

<u><em></em></u>

<u><em>   </em></u>

6 0
3 years ago
What is 140 degrees in radian mesure with multiple of pi
jek_recluse [69]
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8 0
3 years ago
A triangle has a base of (3x + 7) and a height of (5x - 1). A second
Mars2501 [29]

Answer:

The difference between the area of the original triangle and the area of the new triangle is \Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1).

Step-by-step explanation:

The equation for the area of a triangle (A_{\bigtriangleup}) is:

A_{\bigtriangleup} = \frac{1}{2}\cdot b \cdot h

Where:

b - Base, dimensionless.

h - Height, dimensionless.

The expression for each triangle are described below:

First Triangle (b = 3\cdot x + 7, h = 5\cdot x - 1)

A_{\bigtriangleup,1} = \frac{1}{2}\cdot (3\cdot x+7)\cdot (5\cdot x -1)

Second Triangle (b = 3\cdot (3\cdot x+7), h = 2\cdot (5\cdot x -1))

A_{\bigtriangleup,2} = 3\cdot (3\cdot x+7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is:

\Delta A_{\bigtriangleup} = A_{\bigtriangleup,2}-A_{\bigtriangleup,1}

\Delta A_{\bigtriangleup} = 3\cdot (3\cdot x+7)\cdot (5\cdot x-1)-\frac{1}{2} \cdot (3\cdot x+7)\cdot (5\cdot x-1)

\Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1)

The difference between the area of the original triangle and the area of the new triangle is \Delta A_{\bigtriangleup} = \frac{5}{2}\cdot (3\cdot x +7)\cdot (5\cdot x -1).

7 0
3 years ago
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