Answer:
1) 
2) ![\sqrt[3]{y^5}=y^{\frac{5}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D%3Dy%5E%7B%5Cfrac%7B5%7D%7B3%7D)
3) ![\sqrt[5]{a^{12}}=a^{\frac{12}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B12%7D%7B5%7D%20%7D)
4) ![\sqrt[4]{z^{9}}=z^\frac{9}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D%3Dz%5E%5Cfrac%7B9%7D%7B4%7D)
Step-by-step explanation:
1) 
We know that 
So, 
2) ![\sqrt[3]{y^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D)
We know that ![\sqrt[3]{x}=x^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D)
So, ![\sqrt[3]{y^5}=y^{\frac{5}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7By%5E5%7D%3Dy%5E%7B%5Cfrac%7B5%7D%7B3%7D)
3) ![\sqrt[5]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D)
We know that ![\sqrt[5]{x}=x^{\frac{1}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B5%7D)
So, ![\sqrt[5]{a^{12}}=a^{\frac{12}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Ba%5E%7B12%7D%7D%3Da%5E%7B%5Cfrac%7B12%7D%7B5%7D%20%7D)
4) ![\sqrt[4]{z^{9}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D)
We know that ![\sqrt[4]{x}=x^{\frac{1}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B4%7D)
So, ![\sqrt[4]{z^{9}}=z^\frac{9}{4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bz%5E%7B9%7D%7D%3Dz%5E%5Cfrac%7B9%7D%7B4%7D)
Answer:
B if there is an N at the end or beginning of it, Not sure if it cut off or not.
Step-by-step explanation:
Well you would need to do 20(7) to get 140, then multiply that to N. I would say B because I'm assuming you're missing out on some part of it, if it is N at the beginning or end then it is B.
Answer:
Step-by-step explanation:
the two given lines are parallel.
Hence they do not intersect.
or they have no solution.
Answer: Insert a 6. The number divisible by 12 is 14<em><u>6</u></em>4
Step-by-step explanation: Start by dividing 12 into the first two digits.
I am using old-fashioned long division.
<u>1 2</u>
12 ) 14 <u><em>6</em></u>
-<u>12</u>
26. this is the remainder, The next digit has to be a number that when divided by 12 will leave a remainder, that when paired with 4, will be evenly divisible by 12.
6 is that number . When you "bring down" the 6, you will be dividing 26÷12. a 2 goes into the quotient, and in the next step 24 is subtracted from 26; the remainder is 2.
Bring down the 4 and divide 12 into 24. The result is 2 as the quotient. 2 ×12 =24 . 24- 24 is 0
1464 ÷ 12 = 122
Answer:
6 gallons
Step-by-step explanation:
1) $30/10 gallons= $3 per gallon
So...
2) $18/3=<u>6 gallons</u>
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