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Brut [27]
3 years ago
6

A quadratic polynomial which has zeros at -7 and 5. ?

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

Answer:

x^2 + 2x - 35

Step-by-step explanation:

Sum of zeros

= - 7 + 5

= - 2

Product of zeros

= - 7 x 5

= - 35

x^2 - ( sum of zeros )x + product of zeros

= x^2 - ( - 2 ) x + ( - 35 )

= x^2 + 2x - 35

The Quadratic polynomial is x^2 + 2x - 35.

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Use the following function to find the value of each operation.
Murljashka [212]
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>

w(f(m(2))) = 593

<h3>Step-by-step explanation:</h3>

We can write how w(f(m(x))) will be defined but that's too much work and it's only useful when we are evaluating w(f(m(x))) with many inputs.

First let's solve for m(2) first. As you read through this answer, you'll get the idea of what I'm doing.

Given:

m(x) = -4x +1

Solving for m(2):

m(2) = -4(2) +1 \\ m(2) = -8 +1 \\ m(2) = -7

Now we can solve for f(m(2)), since m(2) = -7, f(m(2)) = f(-7).

Given:

f(x)=3x-1

Solving for f(-7):

f(-7)=3(-7)-1 \\ f(-7) = -21 -1 \\ f(-7) = -22

Now we are can solve for w(-22). By now you should get the idea why w(f(m(2))) = w(-22).

Given:

w(x) = x^2 -5x -1

Solving for w(-22):

w(-22) = (-22)^2 -5(-22) -1 \\ w(-22) = 484 -5(-22) -1 \\ w(-22) = 484 +110 -1 \\ w(-22) = 593

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

5:20+40= 6:00

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