Answer:
(4,4)
Step-by-step explanation:
y = 2x - 4 -------eqn 1
4y = x + 12 ------eqn 2
From eqn 1 y = 2x - 4; insert in eqn 2
4 (2x-4) = x + 12 (open the bracket)
8x - 16 = x + 12 (taking like figures to the same side, sign changes)
8x - x = 12 + 16
7x = 28
x = 28/7
x = 4
From eqn 1
y = 2x - 4
y = 2(4) - 4
y = 8 - 4
y = 4
(x,y) = (4,4)
<span>Based on the data in the two-way table, the probability of being older than 25 years and having a hemoglobin level above 11 is
(154-69)/(429-139)
=85/290
=0.2931~0.29
Answer: A. 0.29
</span><span>The probability of having a hemoglobin level above 11 is
P(H>11)
=154/429
=0.35897~0.36
Answer: </span><span>C:0.36
</span><span>Being older than 25 years and having a hemoglobin level above 11
</span>Are not dependent on each other because w have not been told about any factors that were included in selection of sample.
Answer: <span>B.are not</span>
Answer:
It will double in size, as M x M x M x M is simply just 3 changeable values. When we change 4 numbers of a prism (3 changed values ) to all 4 we have a S4 value to the volume, But we didnt do this, applying x 4 to either measurement it can only increase the volume by x 2. We had a one change value SF4 so we have SF 2= double. That means if we have two change value value SF4 we have 3 = 3 x total increase, if we have a three input change by SF4 we can increase size to 4x total increase.
Step-by-step explanation:
Answer: a) 3876 b) 18480
Step-by-step explanation:
Given , The number of professors = 8
The number of students are available = 11
Total persons = 8+11=19
a) The number of ways to select 4 people = 
![=\dfrac{19!}{4!(19-4)!}\ \ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\=\dfrac{19\times18\times17\times16\times15!}{24\times15!}\\=3876](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B19%21%7D%7B4%21%2819-4%29%21%7D%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D%5C%5C%3D%5Cdfrac%7B19%5Ctimes18%5Ctimes17%5Ctimes16%5Ctimes15%21%7D%7B24%5Ctimes15%21%7D%5C%5C%3D3876)
Hence, the number of ways to select 4 people = 3876.
b) Number of ways to choose 3 professors and 4 students = 
Hence, the numbers of ways to form a committee with 3 professors and 4 students = 18480.
