Question

25. What is the equilibrium constant expression for the following? 2Hg (g) + O₂(g) → 2HgO (s) A. K= [Hg] [0₂]. B. K= [HgO]/([Hg]²[0₂]) M C. K=[2HgO]/([2Hg][0₂]). D. K=1/([Hgl [02]) 25. What is the equilibrium constant expression for the following ? 2Hg ( g ) + O₂ ( g ) → 2HgO ( s ) A. K = [ Hg ] [ 0₂ ] . B. K = [ HgO ] / ( [ Hg ] ² [ 0₂ ] ) M C. K = [ 2HgO ] / ( [ 2Hg ] [ 0₂ ] ) . D. K = 1 / ( [ Hgl [ 02 ] )​

Answer 1

Answer:

2 Hg (g) + o2 ---> 2 H2o

equilibrium constant

K = (c) (d) / (a)(b)

K= ( H2o)²/(He) ²(o2)