Well, the keyword here is One of the performers insist on being the last.
So, the amount of performers that we can arrange freely is 7 performers.
Different ways we can schedule their appearance is :
7 ! = 7 x 6 x 5 x 4 x 3 x 2 x 1
= 5040
hope this helps
let each box length be 1
<em><u>for</u></em><em><u> </u></em><em><u>white</u></em><em><u> </u></em><em><u>triangle</u></em>
area = ½bh
=½(4)(2)
=4
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>l</u></em><em><u>e</u></em>
area=½(2)(3)
=3
<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>x</u></em><em><u>e</u></em><em><u>s</u></em>
each of the box
area=l²
=(1)²
=1
there are 16 boxes
so the total area will be 16
total area of the hexagon = 4+3+16
=23 square units
Answer:
Yes
Step-by-step explanation:
A square is a quadlirateral.
A rectangle is a quadrilateral.
Hello!
n<span>≤-1/2 means that n is less than the open circle, because an open circle means the variable can not be equal to that point. so your answer is: D
I hope this helps, and have a nice day.
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