a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean $(\mu) = 5.75913$

Standard deviation $(\sigma) = 0.172229$

Variance $(\sigma2) = 0.0296$

Here we get is

$P(x < \mu - \sigma/2) = p(x < 5.673) \\\\ = 0.3085$

$P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085$

$P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383$

25th percentile:-

$= 25*[(n+1)/100]th term \\\\= 5.69$

75the percentile:-

$= 75*[(n+1)/100]th term\\\\ = 5.87$

$p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707$

7 0

3 years ago

Qual a resposta dessa expressão numérica? 3-10³-3.10².2².1²

Len [333]

I don't understand your language and I don't know which language is this but I try to answer your question. 3-1000-3*100*4*1 3-1000-1200 3-2200 =-2197

6 0

3 years ago