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2 years ago

Which expression shows the sum of the polynomials with like terms grouped together?

Mathematics

1 answer:

NikAS [45]2 years ago

3 0

The expression of the polynomials with like terms grouped together is (c) [-4x²] + 2xy² + [10x²y + (-4x²y)]

<h3>How to group the polynomial by like terms?</h3>

We have:

10x²y + 2xy² - 4x² - 4x²y

Collect the like terms

- 4x² + 2xy² + 10x²y - 4x²y

Put each group in bracket

- 4x² + 2xy² + [10x²y - 4x²y]

Express as positives

[-4x²] + 2xy² + [10x²y + (-4x²y)]

Hence, the expression of the polynomials with like terms grouped together is (c) [-4x²] + 2xy² + [10x²y + (-4x²y)]

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Determine the domain of the function f(x)=1/3x^2+10x+8

cricket20 [7]

The function is
f(x) = (1/3)x² + 10x + 8

Write the function in standard form for a parabola.
f(x) = (1/3)[x² + 30x] + 8
= (1/3)[ (x+15)²- 225] + 8
= (1/3)(x+15)² -75 + 8
f(x) = (1/3)(x+15)² - 67

This is a parabola with vertex at (-15, -67).
The axis of symmetry is x = -15
The curve opens upward because the coefficient of x² is positive.
As x -> - ∞, f -> +∞.
As x -> +∞, f -> +∞
The domain is all real values of x (see the graph below).

Answer: The domain is (-∞, ∞)

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3 years ago

What is the distance between points A and B? Use absolute value to explain your answer.

Alona [7]

Answer:

Input Data :

Point 1(xA,yA)(xA,yA) = (4, 3)

Point 2(xB,yB)(xB,yB) = (3, -2)

Objective :

Find the distance between two given points on a line?

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2

= √(−1)2+(−5)2(-1)2+(-5)2

= √1+251+25

= √2626 = 5.099

Distance between points (4, 3) and (3, -2) is 5.099

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4 years ago

1. Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise. What

Reil [10]

Answer: A'(3,2), B'(0,1) and C'(-4, -5).

Step-by-step explanation:

When we rotate (a,b) 90 degrees clockwise, the new point will be (b,-a).

i.e. rotation rule for 90 degrees clockwise : (x,y) → (y,-x)

Given: Triangle ABC with coordinate points A(-2,3); B(-1,0); C(5,-4) is rotated 90 degrees clockwise.

Then, the new image points for triangle A'B'C' will be :

A(-2,3) → A'(3,-(-2)) =A'(3,2)

B(-1,0)→ B'(0,-(-1)) = B'(0,1)

C(5,-4) → C'(-4, -5)

Hence, the new image points for triangle A'B'C' are A'(3,2), B'(0,1) and C'(-4, -5).

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3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

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3 years ago

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6 cups of flour! Hoped this helps!!

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