All categories

2 years ago

Which expression shows the sum of the polynomials with like terms grouped together?

Mathematics

1 answer:

NikAS [45]2 years ago

3 0

The expression of the polynomials with like terms grouped together is (c) [-4x²] + 2xy² + [10x²y + (-4x²y)]

<h3>How to group the polynomial by like terms?</h3>

We have:

10x²y + 2xy² - 4x² - 4x²y

Collect the like terms

- 4x² + 2xy² + 10x²y - 4x²y

Put each group in bracket

- 4x² + 2xy² + [10x²y - 4x²y]

Express as positives

[-4x²] + 2xy² + [10x²y + (-4x²y)]

Hence, the expression of the polynomials with like terms grouped together is (c) [-4x²] + 2xy² + [10x²y + (-4x²y)]

You might be interested in

If, in 7 years, Susan will be 2 times as old as she was 3 years ago, what is Susan’s present age?

pochemuha

Answer:

Step-by-step explanation:

Set Susan's present age as x, her age from 3 years ago as x-3, and her age in three years as 2(x-3)

Since her age in seven years = 2 times as old as she way 3 years ago, set up the equation:

x+7 = 2(x-3)

x+7 = 2x-6

x = 13

3 0

3 years ago

Write a rule describing the translation below

CaHeK987 [17]

Answer:

d=e

Step-by-step explanation:

3 0

3 years ago

On a coordinate plane, 2 straight lines are shown. The first solid line has a positive slope and goes through (0, negative 2) an

ExtremeBDS [4]

Answer:

$y\geq x-2$

$x+2y$

Step-by-step explanation:

step 1

Find the equation of the first inequality

Find the equation of the first solid line

we have the ordered pairs

(0,-2) and (2,0)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{0+2}{2-0}$

$m=\frac{2}{2}$

$m=1$

The equation in slope intercept form is equal to

$y=mx+b$

we have

$m=1$

$b=-2$ ---> the y-intercept is given

substitute

$y=x-2$

Remember that

Everything to the left of the solid line is shaded

The inequality is

$y\geq x-2$

step 2

Find the equation of the second inequality

Find the equation of the second dashed line

we have the ordered pairs

(0,2) and (4,0)

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{0-2}{4-0}$

$m=\frac{-2}{4}$

$m=-\frac{1}{2}$

The equation in slope intercept form is equal to

$y=mx+b$

we have

$m=-\frac{1}{2}$

$b=2$ ---> the y-intercept is given

substitute

$y=-\frac{1}{2}x+2$

Remember that

Everything below and to the left of the line is shaded

The inequality is

$y$

Rewrite

Multiply by 2 both sides

$2y$

$x+2y$

therefore

The system of inequalities is

$y\geq x-2$

$x+2y$

see the attached figure to better understand the problem

5 0

4 years ago

Read 2 more answers

Does the zoo have enough leaves too feed 5 elephants and 8 giraffes

aleksley [76]

Answer:

yeah probably

Step-by-step explanation:

3 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago