Step-by-step explanation:
let E be weight of expensive nuts, C be cheaper nuts
E*8+C*5=10*6 value equation
E+C=10 mass equation
Solve it by any method, I will do determinants
Det: 8-5=3
E= (60-50)/3=10/3 =3.33 lb
C= 80-60 /3=20/3 =6.66 lb
There's no way to know this without knowing the number of pencils he started with
Equation: 4x + 7 = 3(2x - 5)
Step-by-step solution:
• Expand brackets
-> 4x + 7 = 6x - 15
• Move x variable to a side and the numbers to another
-> 4x - 6x = -15 - 7
• Solve
-> -2x = -22
• Multiply both sides by (-1)
-> -(-2x) = -(-22)
-> 2x = 22
• Divide both sides by 2
-> x = 22/2
-> x = 11
• Justification
-> Put x = 11 in original equation
-> 4(11) + 7 = 3( 2(11) - 5)
-> 44 + 7 = 3(22 - 5)
-> 51 = 3(17)
-> 51 = 51
-> 51 - 51 = 0
-> 0 = 0
Since both sides are equal to each other, the answer to the equation is correct.
I don't know Sam's equation so I'm not gonna answer that.
-7d > 21
d < -3
Remember the sign flips when you multiply or divide by a negative number.
Answer:
8.75cm²
Step-by-step explanation:
First we need to find the angle subtended by the arc
L = theta/360 * 2pir
3.5 = theta/360 * 2*3.14(5)
3.5 = theta/360 * 31.4
theta/360 = 3.5/31.4
theta/360 = 0.11146
theta = 0.11146 * 360
theta = 40.13 degrees
Area of the sector = theta/360 * pir^2
Area of the sector = 40.13/360 * 3.14*25
Area of the sector = 40.13/360 * 78.5
Area of the sector = 8.75cm
Hence the area of the sector is 8.75cm²