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laiz [17]
3 years ago
5

Find the nth term of this number sequence 18, 16, 14, 12,... Pls help

Mathematics
2 answers:
Gnom [1K]3 years ago
4 0

Answer:

20 - 2n

Step-by-step explanation:

The sequence is arithmetic since the difference between consecutive terms is constant, that is

d = 16 - 18 = 14 - 16 = 12 - 14 = - 2

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 18 and d = - 2, thus

a_{n} = 18 - 2(n - 1) = 18 - 2n + 2 = 20 - 2n

a_{n} = 20 - 2n

hodyreva [135]3 years ago
3 0
Step - by - step - explanation

So first find out the pattern. As you can see it just minuses 2 each time. So first

18, 16, 14, 12 (then minus another 2) equals 10, 8, 6, 4, 2.

So 2 is the ninth of the pattern, so 2 will be your answer.

Hope this helps.
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3 years ago
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finlep [7]
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7 0
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Suppose △LPO ≅ △HJU.<br> What is the corresponding congruent parts for each segment or angle?
SashulF [63]

Answer:

NG ( first and last letter of NBG)  = WS ( first and last letter of WTS).

BG = TS

G = S

N =W or NG = WS; BG = TS; G = S; N = W.

Step-by-step explanation:

We use the congruence statement to answer these questions.  From the way the congruence statement is written, we can see that N = W (they are in the same relative position in the congruence statement).  We also see that G and S are in the same relative position, so G = S.

Since N = W and G = S, this means that NG = WS.

From the congruence statement we can also see that B = T (they are in the same relative position).  Since G = S, this means that BG = TS.

5 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

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