Question

Will give brainliest and about 45 points

Answer 1

Answer:

$-\dfrac{3}{4}$

Step-by-step explanation:

Slope-intercept form of a linear equation:

 $y=mx+b$

where:

• m is the slope
• b is the y-intercept

Given linear equation:

  $4x-3y=12$

Find the slope of the given linear equation by rewriting the equation so that it is in slope-intercept form (i.e. make y the subject):

$\implies 4x-3y=12$

$\implies 4x-3y+3y=12+3y$

$\implies 4x=12+3y$

$\implies 4x-12=12+3y-12$

$\implies 4x-12=3y$

$\implies \dfrac{3y}{3}=\dfrac{4}{3}x-\dfrac{12}{3}$

$\implies y=\dfrac{4}{3}x-4$

Therefore, the slope of the given line is 4/3.

If two lines are perpendicular to each other, the product of their slopes will be -1.   Therefore, the slope (m) of the line perpendicular to the given line is:

$\implies m \times \dfrac{4}{3}=-1$

$\implies m=-\dfrac{3}{4}$

Answer 2

Answer:

$\sf C. - \dfrac{3}{4}$

Explanation:

$\sf Given \ equation : 4x - 3y = 12$

Rewrite in slope intercept form "y = mx + b"

$\rightarrow \sf 4x - 3y = 12$

$\rightarrow \sf - 3y = 12 - 4x$

$\rightarrow \sf y =\dfrac{ 12 - 4x}{-3}$

$\rightarrow \sf y =\dfrac{ 4}{3}x - 4$

Here the slope is 4/3 and y-intercept is -4

Perpendicular lines has negatively inverse slope.

→ per. slope = -(slope)⁻¹ = -(4/3)⁻¹ = -3/4