There are various ways in which you could do this problem. I'm going to share what I think is one of the faster ways.
Instead of thinking of jumping from (-1,4) TO (2,-2), Consider the horiz. jump separately and the vertical jump separately. From -1 to 2 is 3 units. Three times that is 9 units. Add 9 to -1, obtaining 8. That's the horiz. component of the terminal point.
From 4 to -2 is -6 units. Mult. that by 3. The result is the vert. comp of the terminal point.
What are the following questions because they aren’t there
To obtain the total surface we have to calculate the surface of the 4 triangles and add up the areas (remember that the area of a triangle is (b*h)/2 , b is the base, h is the height ).
We will caculate first the area of the base triangle for that we considerer the fact that it is an equilateral triangle with sides of lenght 6 cm, now we calculate the height, I am going to draw please wait a moment
using the pythagorean theorem we have that
![\begin{gathered} h^2=6^2cm^2-3^2\operatorname{cm}=27cm^2 \\ h=\text{ }\sqrt[]{27\text{ }}cm \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2cm%5E2-3%5E2%5Coperatorname%7Bcm%7D%3D27cm%5E2%20%5C%5C%20h%3D%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B27%5Ctext%7B%20%7D%7Dcm%20%5Cend%7Bgathered%7D)
Then, the area of the triangle is 6*h/2 = 3h = 15.59 cm^2.
Now we calculate the area of the other 3 triangles, notice that those triangles have the same base and height so we will calculate for one of them and multiply by 3. From the image we know that the height is 15cm and the base is 6 cm so the area is 45cm^2, and 45*3 cm^2 = 135cm^2.
Finally we add up all the areas:
For this case we have the following expression:
x ^ 2 + 15x + 56
We can factor this expression to find the possible dimensions of the rectangle.
Factoring we have:
(x + 7) (x + 8)
Answer:
the possible dimensions are:
(x + 7) * (x + 8)
Answer:
C is correct
Step-by-step explanation:
-3(2b+9) + 5 (-5b+ 6)
-6b-27 -25b +30
-31b+3