Answer:
where is the question i can't see it
Answer:
I think the heat on the surface or the fire under the dish cost evaporation coz when the water got heat tge water evaporate or go to the upper part of dish and cool down then back to the bottom.
Explanation:
Plss correct me if im wrong
Answer:
P = 2.65 E-3 mm Hg
Explanation:
liquid-vapor equilibrium:
⇒ ec. Clausius-Clapeyron:
- Ln (P2/P1) = - ΔHv/R [ (1/T2) - (1/T1) ]
∴ R = 8.314 E-3 KJ/K.mol
∴ ΔHv = 59.11 KJ/mol
∴ T2 = 25°C ≅ 298 K
∴ T1 = 356.7°C = 629.7 K
normal boiling point:
∴ P = 1 atm = P1 = 101.325 KPa
vapor pressure (P2):
⇒ Ln P2 - Ln (101.325) = - (59.11 KJ/mol)/(8.314 E-3 KJ/K.mol)*[ (1/298) - (1/629.7) ]
⇒ Ln P2 - 4.618 = - (7109.694 K)*[ 1.7676 E-3 K-1 ]
⇒ Ln P2 = 4.618 - 12.567
⇒ P2 = e∧(-7.9494)
⇒ P2 = (3.5313 E-4 KPa)×(7.50062mm Hg/KPa) = 2.65 E-3 mm Hg