Explanation:
Grey Goose vodka has an alcohol content of 40.0 % (v/v).
Volume of vodka = V = 100 mL
This means that 40.0 mL of alcohol is present 100 mL of vodka.
Volume of ethanol=V' = 40.0 mL
Mass of ethanol = m
Density of the ethanol = d = 0.789 g/mL
Volume of water = V''= 100 ml - 40.0 mL = 60.0 mL
Mass of water = m'
Density of the water = d' = 1.00 g/mL
a.)
Moles of ethanol = n=
Volume of vodka = V = 100 mL = 0.100 L ( 1mL=0.001 L)
Molarity of the ethanol:
6.861 M the molarity of ethanol in this vodka.
b) Mass of ethanol = 31.56 g
Moles of ethanol = n=
Volume of vodka = V = 100 mL
Mass of vodka = m
Density of the water = D = 0.935 g/mL
The percent by mass of ethanol % (m/m):
33.75% is the percent by mass of ethanol % (m/m) in this vodka.
c)
Moles of ethanol = n=
Mass of solvent that is water = 60.0 g = 0.060 kg ( 1g = 0.001 kg)
Molality of ethanol in vodka :
11.435 m is the molality of ethanol in this vodka.
d)
Moles of ethanol =
Moles of water =
Mole fraction of ethanol =
= 0.1707
Mole fraction of water =
= 0.8290
e)
The vapor pressure of vodka = P
Mole fraction of ethanol =
Mole fraction of water =
The vapor pressures of ethanol =
The vapor pressures of pure water =
The vapor pressure of vodka is 27.41 Torr.
