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Andreyy89
3 years ago
14

19. Chemical properties can be used to

Chemistry
1 answer:
RoseWind [281]3 years ago
7 0

Answer:differentiate between two compounds i think!

Explanation: taking a test!

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C9H20 +<br> 02 - &gt; CO2 +<br> H2O<br><br> what is the balanced equation of this
san4es73 [151]

Hey there!

C₉H₂O + O₂ → CO₂ + H₂O

First let's balance the C.

There's 9 on the left and 1 on the right. So, let's add a coefficient of 9 in front of CO₂.

C₉H₂O + O₂ → 9CO₂ + H₂O

Next let's balance the H.

There's 2 on the left and 2 on the right. This means it's already balanced.

C₉H₂O + O₂ → 9CO₂ + H₂O

Lastly, let's balance the O.

There's 3 on the left and 19 on the right. So, let's add a coefficient of 9 in front of O₂.

C₉H₂O + 9O₂ → 9CO₂ + H₂O

This is our final balanced equation.

Hope this helps!

8 0
2 years ago
What gives the gem amethyst its purplish color?
Aleks [24]
Answer will be B:Iron
6 0
3 years ago
Read 2 more answers
A cylindrical glass tube of length 27.4cm and radius 4 cm is filled with gas. The empty tube has a mass of 254.3 g. The tube fil
Temka [501]

Density of the gas is 3.05 × 10⁻³ g / cm³.

<u>Explanation:</u>

Volume of the cylinder = π r² h

where r is the radius and h is the height of the height or the length of the glass tube.

Here r = 4 cm and h = 27.4 cm

Volume of the cylinder = 3.14 × 4 × 4 × 27.4 = 1376.6 cm³

We have to find the mass of the gas by subtracting the mass of the tube filled with the substance from the mass of the empty tube.

Mass of the substance = 258.5 - 254.3 = 4.2 g

We have to find the density using the formula as,

$ Density = \frac{mass}{volume}

Plugin the values as,

$ Density = \frac{4.2}{1376.6}

              = 3.05 × 10⁻³ g / cm³

So the Density of the gas is 3.05 × 10⁻³ g / cm³.

3 0
2 years ago
Retry: 1.Examine Record A. Use the three basic rules to figure out the ages of the layers. In Chart A, list the layers from youn
zubka84 [21]
I, D, B, E, H, C, J, F, A, G, K
7 0
3 years ago
Read 2 more answers
If 0.034 moles of potassium nitrate were formed how many moles of lead (II) nitrate did you start
uranmaximum [27]

Answer:

0.017 mole of Pb(NO₃)₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KOH + Pb(NO₃)₂ —> 2KNO₃ + Pb(OH)₂

From the balanced equation above,

1 mole of Pb(NO₃)₂ reacted to produce 2 moles of KNO₃.

Finally, we shall determine the number of mole of Pb(NO₃)₂ required to produce 0.034 mole of KNO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of Pb(NO₃)₂ reacted to produce 2 moles of KNO₃.

Therefore, Xmol of Pb(NO₃)₂ will react to produce 0.034 mole of KNO₃ i.e

Xmol of Pb(NO₃)₂ = 0.034 / 2

Xmol of Pb(NO₃)₂ = 0.017 mole.

Thus, 0.017 mole of Pb(NO₃)₂ is needed for the reaction.

6 0
3 years ago
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