The NaOH can react with HCl with the formula: NaOH + HCl = NaCl + H2O. So if you want to neutralize the solution, the molar number of NaOH and NCl need to be equal. So we need 0.3*50/0.1=150 milliliters.
Carbonic acid.............................................
Answer: 4.99×10²³ photons
Explanation: The energy of a photon is given as
E= hf
h= Planck constant = 6.626×10^-34Js
f= frequency = c/x
C= speed of light = 3×10^8 m/s
x= wavelength= 525nm= 525×10^-9
E= hc/x
E= 6.626×10^-34 × 3×10^8 m/s /( 525×10^-9)
E= 3.79×10^−19 J/ Photon
E= 3.79×10^−22KJ/Photon
189KJ/3.79×10^−22KJ/photon=
4.99×10²³photons.
Therefore the number of photons is
4.99×10²³photons.
Explanation:
The given data is as follows.
Concentration of acid, [HF] = 2 M
Concentration of salt, [NaF] = 0.472 M
Concentration of base, [NaOH] = 1.00 M
=
So, NaOH being a base will react with the acid that is, HF. And, according to Henderson-Hasselbalch equation we have he following.
pH =
Also, we known that
so,
= 3.1426
Hence, pH =
pH = 2.5155
Thus, we can conclude that pH of the solution is 2.5155.