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vladimir2022 [97]
3 years ago
15

How many grams are in 36.2 moles of Iron (I) fluoride?

Chemistry
2 answers:
Semmy [17]3 years ago
7 0

Answer:

The person above is correct

Explanation:

Allushta [10]3 years ago
5 0

Answer:

4084.808 grams (SigFigs: 4085 grams)

Explanation:

The molar mass of Iron fluoride is 112.84 g/mol.

To calculate the mass, multiply the molar mass by the number of moles.

36.2 mol * 112.84 g/mol = 4084.808 g

Convert to Sigfigs (if necessary):

4085 g

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4 years ago
Using the nernst equation calculate the cell voltage for: fe(s) + cd2+(aq) â fe2+(aq) + cd(s) when the [fe2+] = 0.10 m and [cd2+
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The Nernst equation is:

E = E° - RTlnK/nF
where
E° is the standard potential voltage
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Let's determine K first. The overall reaction is:

Fe(s) + Cd²⁺(aq) --> Fe²⁺(aq) + Cd(s)
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From the reactions written, you can see that 2 electrons were transferred. So, n = 2.

Lastly, the value for E⁰ is the sum of individual E⁰ of the reactions.
E⁰ = E⁰cathode - E⁰anode
Cathode reaction: Fe(s) --> 2e + Fe²⁺ (E⁰cathode = 0.44 V)
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Substituting the values (assume T at room temperature = 298 K),
E = 0.84 - (8.314)(298 K)(ln 1/14)/(2)(96,500)
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<em />

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What would be the advantage of using a molecular model.
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