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DochEvi [55]
2 years ago
10

2. Simplify the expression. (x3)(x7)² 1 x18 x14 x126

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
4 0

Step-by-step explanation:

= ( {x}^{3} ) { ({x}^{7} )}^{2}

=  {x}^{3}  \times  {x}^{7 \times 2}

=  {x}^{3}  \times  {x}^{14}

=  {x}^{3 + 14}

=  {x}^{17}

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Determine if the function is one-to-one. A parabola is shown facing up with a vertex of 2.5, -6
Elina [12.6K]

<u>ANSWER</u>

It is not one-to-one function

<u>EXPLANATION</u>

A one-to-one function must pass the horizontal line test.

The graph described in the question looks like the one in the attachment.

A horizontal line drawn in red cuts the graph at more than one point.


Therefore the parabola shown facing up with a vertex (2.5, -6) is not a one-to-one function.

3 0
3 years ago
Can someone answer this question for me pls n thanks
allsm [11]

Answer:

Mean: 29.5;    Median: 26;    Modes: 25, 26

Step-by-step explanation:

Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354

Then divide it by 12      354/12 = 29.5

Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.

8 0
2 years ago
Which strategy should be used to correctly solve this problem?
hammer [34]
B, make a table of possible values

the best way to do it is actually not listed
to have max area with minimu perimiter, try to get the sides as close measure to each other as possible


I would pick B though

6 0
3 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
Which statements are true?
rjkz [21]

Answer:

Step-by-step explanation:

There's only one correct answer, and you've already responded with that answer.

6 0
3 years ago
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