Answer:
12
Step-by-step explanation:
Answer:
(c) (12th root of 8)^x
Step-by-step explanation:
The applicable rules of exponents are ...
![(a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}](https://tex.z-dn.net/?f=%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B1%20%5C%21%20%2Fn%7D)
In this case, we have ...
![(\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B8%7D%29%5E%7Bx%2F4%7D%3D8%5E%7B1%2F3%5Ccdot%20x%2F4%7D%3D8%5E%7Bx%2F12%7D%3D%5Cboxed%7B%5Cleft%28%5C%21%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5Ex%7D)
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Step-by-step explanation:
I'll solve it by substitution instead of graphing.
x + y = 2
y = (1/2)x + 5
Substitute equation 2 into equation 1.
x + (1/2)x + 5= 2
(3/2)x + 5 = 2
(3/2)x + 5 - 5 = 2 - 5
(3/2)x = -3
(2/3) * (3/2)x = -3 * (2/3)
x = -2
x + y = 2
-2 + y = 2
y - 2 = 2
y - 2 + 2 = 2 + 2
y = 4
x = -2
y = 4
(-2,4)
Your answer is B) (-2,4).