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irinina [24]
2 years ago
13

Which statements are correct based on the graph? Select all that apply.

Mathematics
1 answer:
tangare [24]2 years ago
8 0

Answer:

2,3,4

Step-by-step explanation:

hope this helps=D

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What are the odd numbers
Ivan

Answer:

1,3,5,7,9....up to soon are odd numbers

Step-by-step explanation:

they are not divided by 2

4 0
4 years ago
Read 2 more answers
HELP ASAP
lora16 [44]
I solved it on a piece of paper. I can not answer why I got the same answer, but I hope my method helped

3 0
3 years ago
What’s the commutative steps to multiply 3 times 10 cubed and 2 times 10 to the 4th power
DerKrebs [107]

Answer:

23000

Step-by-step explanation:

6 0
3 years ago
A famous basketball player scored 97 points in a high scool game, breaking a national record. She made 43 more 2-point baskets t
ziro4ka [17]
X - 3pt  baskets  (he reaches 3x points)
y - 2pt baskets  (he reaches 2y points)

We know, that  y=x+43

97 - 1 free throw = 97 - 1 = 96
Sum of points:  96

3x + 2y = 96.   Substitute  to "y"  an expression "x+43" :

3x + 2(x+43)=96
3x+2x+86=96
5x=10    |:5
x=2 

So y=x+43=2+43=45 

He has made 2  three points baskets and 45 two points baskets
8 0
3 years ago
(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

5 0
3 years ago
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