Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
Answer:
46 mph and 61 mph
Step-by-step explanation:
Distance=speed*time
Let speed of one bus be x and another x+15
After 3 hours
First bus would have traveled 3x while second bus 3(x+15)=3x+45
Total distance= 3x+3x+45=6x+45
6x+45=321
6x=321-45=276
x=276/6=46 mph
x+15=46+15=61 mph
1/3 = 8/24
1/4 = 6/24
An Answer to 31 is 7/24
0.89
0.90
An Answer to 32 is 0.895
-2/3
1/2
An Answer to 33 is -1/2
0.27 = 27/100
4/5 = 80/100
An Answer to 34 is 54/100 = 27/50
Area is squared so divide 56/6 gives you 9.3 round down so length of base is 9 m.